2011 JAMB PHYSICS PAST QUESTIONS AND ANSWERS Leave a Comment / Jamb Physics / By Jamb Tutor Report a question What’s wrong with this question? You cannot submit an empty report. Please add some details. 0% Created by Jamb TutorJamb Physics 2011 JAMB PHYSICS PAST QUESTIONS AND ANSWERS 1 / 50 Category: JAMB Physics 2011 1. Which Physics Question Paper Type is given to you? a) Type A. b) Type B. c) Type C. d) Type D. Paper type is identified by options A to D. Question specifies Type C, making it correct. 2 / 50 Category: JAMB Physics 2011 2. A carpenter dropped a hammer (1.5 kg) from 20 m roof. Kinetic energy before hitting? a) 450 J. b) 600 J. c) 150 J. d) 300 J. KE = mgh = 1.5 × 10 × 20 = 300 J. Correct answer is 300 J. 3 / 50 Category: JAMB Physics 2011 3. Positions of balls X (5g) and Y (50kg) after being thrown vertically at ${100 ms}^{-1}$ after 1 second? a) Both 500m away. b) 500m apart. c) Y ahead. d) X ahead. All objects fall under gravity equally; positions will be the same, unaffected by mass difference. 4 / 50 Category: JAMB Physics 2011 4. Why does a man in a descending lift feel weightless? a) No gravity. b) Airtight lift. c) Lift in vacuum. d) No floor reaction. No reaction force from floor; normal force is zero, making the man feel weightless. 5 / 50 Category: JAMB Physics 2011 5. Resultant of vectors at right angles: sides are 5 N and 12 N. Find resultant. a) 13.0 N. b) 14.0 N. c) 10.0 N. d) 12.0 N. Resultant $R = \sqrt{(5)^2 + (12)^2} = 13$ N. Use Pythagoras theorem. 6 / 50 Category: JAMB Physics 2011 6. Centripetal force on 2 kg object moving at ${10 ms}^{-1}$ in 4 m radius circle? a) 40 N. b) 25 N. c) 100 N. d) 50 N. $F = mv^2/r = 2 \times (10)^2/4 = 50$ N. 7 / 50 Category: JAMB Physics 2011 7. Object falls freely for 3 seconds. Distance covered? [g = ${10 ms}^{-2}$] a) 60 m. b) 90 m. c) 30 m. d) 45 m. $s = 0.5gt^2 = 0.5 × 10 × 9 = 45$ m. Correct distance is 45 m. 8 / 50 Category: JAMB Physics 2011 8. Position(s) of neutral equilibrium of cone (see diagrams)? a) Y and X. b) Z only. c) X only. d) Y and Z. Neutral equilibrium is when displacement does not alter center of gravity; position Z qualifies. 9 / 50 Category: JAMB Physics 2011 9. Tube of small radius in liquid; what happens if liquid wets or doesn’t wet glass? a) Rise if no wetting. b) Remain same level. c) Fall if wets glass. d) Fall if no wetting. Capillarity causes rise if it wets, fall if it doesn’t wet the glass. Answer depends on liquid property. 10 / 50 Category: JAMB Physics 2011 10. What determines liquid pressure: density, depth, or surface area? a) I and III only. b) I and II only. c) II and III only. d) I, II, III. Pressure depends on density and depth only (P = ρgh); surface area doesn’t affect it. 11 / 50 Category: JAMB Physics 2011 11. Qualities of a good thermometer: thermal capacity, sensitivity, readability, accuracy? a) II, III, IV. b) I and II. c) I, II, III, IV. d) I, III, IV. All four (I, II, III, IV) are essential qualities of a good thermometer for accurate and readable temperature measurements. 12 / 50 Category: JAMB Physics 2011 12. Machine lifts load of 20N through 10m, efficiency = 40%; find work done. a) 120 J. b) 80 J. c) 500 J. d) 300 J. Efficiency = (useful work done / work input) × 100. Work input = 20 × 10/0.4 = 500 J. 13 / 50 Category: JAMB Physics 2011 13. Which of the following is most effective in reducing friction: petrol, kerosene, grease, or water? a) Petrol. b) Kerosene. c) Grease. d) Water. Grease is commonly used to reduce friction in machinery because of its viscosity and staying power on surfaces. 14 / 50 Category: JAMB Physics 2011 14. Copper wire tensile stress is ${7.7 \times 10^7 Nm}^{-2}$, Young’s modulus ${1.1 \times 10^{11} Nm}^{-2}$. Find strain. a) ${2.2 \times 10^{-4}}$ b) ${2.0 \times 10^{-5}}$ c) ${7.0 \times 10^{-3}}$ d) ${7.0 \times 10^{-4}}$ Strain = stress/Young’s modulus = ${7.7 \times 10^7}/{1.1 \times 10^{11}} = 7.0 \times 10^{-4}$. 15 / 50 Category: JAMB Physics 2011 15. Object weighs 22 kg in water, 30 kg in air; calculate upthrust. g = ${10 ms}^{-2}$ a) 80 N. b) 50 N. c) 520 N. d) 220 N. Upthrust = weight in air – weight in water = (30 – 22) × 10 = 80 N. 16 / 50 Category: JAMB Physics 2011 16. 30 W heater raises aluminum block temperature by 100 °C in 5 minutes. Find heat capacity. a) ${200 JK}^{-1}$ b) ${900 JK}^{-1}$ c) ${90 JK}^{-1}$ d) ${100 JK}^{-1}$ Heat = power × time = 30 × 300 = 9000 J. Heat capacity = heat/temp change = 9000/100 = 90 J/K. 17 / 50 Category: JAMB Physics 2011 17. Perfect absorber or emitter of radiant energy is called? a) Red body. b) Conductor. c) Black body. d) White body. Black bodies are ideal emitters/absorbers in radiation physics. 18 / 50 Category: JAMB Physics 2011 18. Which phenomenon demonstrates that pressure lowers melting points? a) Regelation. b) Sublimation. c) Condensation. d) Coagulation. Regelation (refreezing) happens when ice melts under pressure and refreezes when pressure is released. 19 / 50 Category: JAMB Physics 2011 19. Gas volume increases as temperature decreases at constant pressure. Law obeyed? a) Charles' law. b) Graham's law. c) Boyle's law. d) Pressure law. Charles’ law states V ∝ T (volume directly proportional to temperature at constant pressure). 20 / 50 Category: JAMB Physics 2011 20. Steam burn vs boiling water burn: which is more severe and why? a) Depends on humidity. b) Independent of humidity. c) Steam has higher heat energy. d) Water boils higher. Steam contains latent heat, making burns more severe compared to boiling water of the same temperature. 21 / 50 Category: JAMB Physics 2011 21. Which wave requires a medium for propagation? Sound, light, or radio? a) X-rays. b) Sound waves. c) Light waves. d) Radio waves. Sound waves need a medium, unlike light or radio waves which are electromagnetic and propagate in a vacuum. 22 / 50 Category: JAMB Physics 2011 22. Why is the ground cold at night? Reflection, radiation, or lack of sun? a) Atmosphere reflects sun's energy. b) Atmosphere absorbs sun's energy. c) Earth radiates heat. d) No sunlight. The earth radiates heat to the atmosphere at night, losing heat without sunlight to replenish it. 23 / 50 Category: JAMB Physics 2011 23. Metal volume = ${40cm}^3$; temperature rises from 30°C to 90°C; α = ${2 \times 10^{-5} K}^{-1}$. Find volume increase. a) ${0.40 cm}^3$ b) ${0.14 cm}^3$ c) ${0.12 cm}^3$ d) ${1.20 cm}^3$ Volume expansion $\Delta V = \beta V_0 \Delta T$, $\beta = 3\alpha$. $\Delta V = 3 \times 2\times 10^{-5} \times 40 \times 60 = 0.12 cm^3$. 24 / 50 Category: JAMB Physics 2011 24. Which kinetic theory processes: change of state, diffusion, radiation, osmosis? a) I, II, IV. b) I, II, III, IV. c) I, II, III. d) I, III, IV. Kinetic theory explains state change, diffusion, and radiation based on particle motion, not osmosis. 25 / 50 Category: JAMB Physics 2011 25. What is the defect called when the human eye loses accommodation? a) Long-sightedness. b) Short-sightedness. c) Presbyopia. d) Astigmatism. Presbyopia, often age-related, causes inability to focus on objects at varying distances. 26 / 50 Category: JAMB Physics 2011 26. Wire frequency changes from 255 Hz under 225 N to 324 N tension. Find new frequency. a) 356 Hz. b) 306 Hz. c) 512 Hz. d) 488 Hz. Frequency ratio $\sqrt{F_2/F_1}$; new $f = 255 \sqrt{324/225} \approx 306$ Hz. 27 / 50 Category: JAMB Physics 2011 27. Power of converging lens for far-sighted person who can’t see closer than 50 cm, but needs 25 cm. a) 0.04 D. b) 0.06 D. c) 0.02 D. d) 0.03 D. Power $P = 1/f$; $f = (50 \times 25)/(50-25)$ cm = 25 cm = 0.04 D. 28 / 50 Category: JAMB Physics 2011 28. Electromagnetic wave with the highest frequency: X-rays, UV, radio, or infrared? a) X-rays. b) Ultra-violet rays. c) Radio waves. d) Infrared rays. X-rays have the highest frequency among the options, followed by UV, infrared, and radio waves. 29 / 50 Category: JAMB Physics 2011 29. Red rose in blue light appears: yellow, red, blue, or magenta? a) Yellow. b) Red. c) Blue. d) Magenta. Red rose absorbs blue light and appears black or blue depending on dye and pigment absorption. 30 / 50 Category: JAMB Physics 2011 30. Under what condition does a solar eclipse occur? a) Moon's umbra on Earth. b) Moon between sun and Earth. c) Earth between sun and moon. d) Moon not hidden fully. A solar eclipse happens when the moon is between the earth and sun, casting its umbra on the earth. 31 / 50 Category: JAMB Physics 2011 31. Time taken for sound to travel 4.95 km if speed of sound is 333 m/s. a) 15 s. b) 0 s. c) 10 s. d) 12 s. Time $t = d/v = 4950/333 = 15$ seconds. 32 / 50 Category: JAMB Physics 2011 32. Upright magnified image from convex lens with m=3 and f=15 cm. Find object distance. a) 14 cm. b) 10 cm. c) 25 cm. d) 26 cm. For upright magnified image, $u=f(m+1)/m = 15(3+1)/3 = 20$ cm. 33 / 50 Category: JAMB Physics 2011 33. Capacitance of parallel plate capacitor in air = 20 μF; with dielectric = 60 μF. Find dielectric constant. a) 2.0. b) 0.3. c) 6.0. d) 3.0. Dielectric constant $K = C_{\text{with dielectric}} / C_{\text{air}} = 60 / 20 = 3.0$. 34 / 50 Category: JAMB Physics 2011 34. Three resistors (2Ω, 4Ω, 12Ω) in parallel with 12V across them. Find current through 12Ω resistor. a) 9.6 A. b) 14.4 A. c) 1.0 A. d) 3.2 A. Current $I = V/R = 12/12 = 1$ A. 35 / 50 Category: JAMB Physics 2011 35. Find cost of running appliance rated at 2.5 V, 2 A for 6 hours if charge per kWh is ₦4. a) ₦24. b) ₦0.12. c) ₦12. d) ₦16. Energy $E = VIt$; Cost = $E \times$ rate. $E = 2.5 \times 2 \times 6/1000 = 0.03$ kWh; cost = $0.03 \times 4 = $ ₦12. 36 / 50 Category: JAMB Physics 2011 36. Expression for potential at distance r from charge q in electric field. a) q / 4GOr². b) q / 4GOr. c) q/2 4GOr². d) q/2 4GOr. Potential $V = q / (4\pi\epsilon_0 r)$. 37 / 50 Category: JAMB Physics 2011 37. Three 2V cells with 2Ω resistance each connected in parallel. Find total emf and resistance. a) 6 V, 0.7Ω. b) 6 V, 6.0Ω. c) 2 V, 0.7Ω. d) 2 V, 6.0Ω. Total emf in parallel = single emf = 2 V; resistance in parallel: $1/R = 1/2 + 1/2 + 1/2 \Rightarrow R=2/3Ω$. 38 / 50 Category: JAMB Physics 2011 38. Why are electrical appliances connected in parallel in homes? a) Less voltage. b) Parallel doesn't heat wires. c) Series needs high voltage. d) Less current. Parallel connection ensures each appliance receives full voltage, improving efficiency and independence. 39 / 50 Category: JAMB Physics 2011 39. Two resistors (5Ω and 10Ω) in series then parallel to 24V. Find power ratio series:parallel. a) 3:05 b) 5:03 c) 1:50 d) 50:01:00 Series: $R_{\text{total}} = 15Ω$; Parallel: $1/R_{\text{total}} = 1/5 + 1/10 \Rightarrow R_{\text{total}}=10/3Ω$. Power ratio $P_s:P_p = (V^2/R_s):(V^2/R_p) = 3:5$. 40 / 50 Category: JAMB Physics 2011 40. In electrolysis, when metal X is used, the anode and cathode arrangements include high current usage. Identify X’s role. a) Y anode with high current. b) X anode with c) X cathode and Y anode. d) Y cathode and X anode Metal X acts as the cathode, while Y serves as the anode in electrolysis. The high current is crucial for the reaction’s progression. 41 / 50 Category: JAMB Physics 2011 41. Radioactive isotope decay constant = ${10^{-5} s}^{-1}$. Find its half-life. a) ${6.93 \times 10^4}$ s. b) ${6.93 \times 10^{-6}}$ s. c) ${6.93 \times 10^{-5}}$ s. d) ${6.93 \times 10^5}$ s. Half-life $T_{1/2} = \ln(2) / \lambda = 0.693 / 10^{-5} = 6.93 \times 10^4$ s. 42 / 50 Category: JAMB Physics 2011 42. Properties of steel include? a) Easily magnetized/demagnetized. b) Cannot retain magnetism. c) Used for temporary magnets. d) Ideal for permanent magnets. Steel is ideal for making permanent magnets due to its ability to retain magnetism longer than iron. 43 / 50 Category: JAMB Physics 2011 43. Threshold frequency $f_0 = 1.3 \times 10^{15}$ Hz. Work function? (h = ${6.6 \times 10^{-34}}$ Js) a) ${8.85 \times 10^{-18}}$ J. b) ${8.58 \times 10^{-19}}$ J. c) ${8.58 \times 10^{-15}}$ J. d) ${8.58 \times 10^{-17}}$ J. Work function $\phi = hf_0 = (6.6 \times 10^{-34}) \times (1.3 \times 10^{15}) = 8.58 \times 10^{-19}$ J. 44 / 50 Category: JAMB Physics 2011 44. In an AC circuit, what is the ratio of RMS current to peak current? a) $1/\sqrt{2}$ b) $\sqrt{2}$ c) 2 d) 2-Jan The RMS value is $I_{\text{rms}} = I_{\text{peak}} / \sqrt{2}$. Thus, the ratio is $1/\sqrt{2}$. 45 / 50 Category: JAMB Physics 2011 45. Inductors of 4H and 8H in series with 10A current. Find stored energy. a) 250 J. b) 500 J. c) 50 J. d) 133 J. Energy stored $E = \frac{1}{2} L I^2$. Total $L = 4 + 8 = 12$ H. Energy $E = \frac{1}{2} \times 12 \times 10^2 = 600$ J. 46 / 50 Category: JAMB Physics 2011 46. Conditions under which gases conduct electricity. a) High pressure, high p.d. b) Low pressure, low p.d. c) Low pressure, high p.d. d) High pressure, low p.d. Gases conduct electricity efficiently under low pressure and high potential difference. 47 / 50 Category: JAMB Physics 2011 47. Instrument used to measure high-frequency AC. a) Hot wire ammeter. b) DC ammeter. c) Moving coil ammeter. d) Moving iron ammeter. A hot wire ammeter is designed specifically to measure high-frequency alternating currents. 48 / 50 Category: JAMB Physics 2011 48. Bond between silicon and germanium. a) Electrovalent. b) Covalent. c) Ionic. d) Dative. The bond between silicon and germanium is covalent as both are semiconductors sharing electrons. 49 / 50 Category: JAMB Physics 2011 49. Which materials increase resistance with temperature? a) Electrolyte. b) Water. c) Metals. d) Wood. Metals experience increased resistance with a rise in temperature due to increased ion-electron collision. 50 / 50 Category: JAMB Physics 2011 50. Adding impurities to germanium to alter its electrical properties is called? a) Doping. b) Saturation. c) Bonding. d) Amplification. The process of adding impurities to semiconductors like germanium to modify their properties is known as doping. Your score is The average score is 0% LinkedIn Facebook Twitter VKontakte 0% Restart quiz Anonymous feedback Send feedback
